Descartes' Lost Theorem
S - A + H = 2
with an emphasis on the ``2." This is a slight anachronism because Euler would certainly never have thought of his theorem that way. What has happened in the last 100 years is that many other shapes have been studied besides convex polyhedra, and that (under certain natural hypotheses) it has been discovered that the analogue of S - A + H only depends on the topology: it does not matter how the space is dissected into 0, 1, 2, 3, ... dimensional elements. As long as they are cells, i.e. topologically like points, edges, faces, etc., and fit together roughly like the elements of a polyhedron, the alternating sum
(# of 0-dim elements) - (# of 1-dim elements) + (# of 2-dim elements) - (# of 3-dim elements) + ...
only depends on the topology of the space you start with. In honor of Euler's discovery that this number is always 2 for a convex polyhedron, it is called the Euler characteristic of the space.
Let us compute the Euler characteristic for a surface which is not a convex polyhedron.
_____________________ / / /| / _____/_____ / | / / / / / / / |________/ / / / / / / / / / / / / / / / /__________/ / / / / / / /__________/_________/ / | | / |____________________|/ A cellular dissection of the surface of a torus. |
This picture represents a dissection of the surface of a torus into cells. (The hidden sides are partitioned like the visible ones). There are 24 vertices (0-dimensional cells), 36 edges (1-dimensional cells) and 12 faces (2-dimensional cells). The alternating sum is 0, which is the Euler characteristic of this surface. Note that if the top and bottom had been left as annuli (topologically not cells) the numbers would have been 16, 24, 12. The theorem requires cells. |
For further thought. Cut this toroidal surface into triangles and recompute the Euler characteristic. Calculate the Euler characteristic for the surface of a 2-handled torus (you should get -2). Generalize. Calculate the Euler characteristic of the Klein bottle.