Sample problem.
Let us start with a simple non-periodic function
like f(t) = 2sin(t) - 3sin(21/2t).
Suppose that we know that the function is of the form f(t) = B1sin(t) + B2sin(21/2t), and are given the curve. How to calculate the coefficients B1 and B2?
Tools from trigonometry.
The solution.
To calculate B1: multiply
f(t) by sin(t) and compute twice the
long-term average value of the product. This number must be
B1. Why? The product is
To calculate B2: multiply f(t) by sin(21/2t) and compute twice the long-term average value of the product. This number must be B2.
The following graph shows how the multiplications and long-term averaging tease out the coefficients B1 = 2 and B2 = -3.
erratum "sin(vt)" corrected 7/14/05.
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