Theorem One
In which I showed that 1 was equal to 2. Which it isn't. Could you find
the mistake in my "proof"?
If a=b then a-b=0. Let's look at the critical
lines of the proof again:
a²-ab=(a-b)(a+b)
a(a-b)=(a-b)(a+b)
a=a+b
a=a+a
a=2a
1=2
Can you see the problem now?
Let me narrow it down a little further:
a(a-b)=(a-b)(a+b)
a=a+b
Remember, a-b=0. In the step between these two lines
I am dividing by zero, which is not a well-defined mathematical
operation.
The proof is invalid.
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