PROBLEM OF THE MONTH
April 2005
Congratulations to Jonathan Inbal and Clayton Bailey-Assan, who solved this problem!
Hint: Start with n=2, and then try to work out the cases n=3,4,... Partial proofs (e.g. for n=5) will be considered.
Remark (thanks to Jonathan Inbal and Clayton Bailey-Assan). Some non-degeneracy assumptions are needed here. E.g. if there are only four points lying on the same line, then the statement is obviously wrong. But this is a degenerate case. You may assume, for example, that no triple of points is collinear.
This month's prize will be awarded to the best explained, correct solution.
Closing date: May 10th at 12 pm.