Start  suppose theres something that looks like this if you see this the first thing you should know is e to the 2x is what what you have when you have x and square it if e to the x squared of x dont confuse that a e to the x squared 
0:31  anyway so thius.. what you can do is you can look at this and say
see how that power is twice as big as that power?
its kind of like one of those quadratic things if you love some of them so why dont i do smething like this? if i let y=e to the x i can rewrite this y squared 6y7=0 
1:00  then i could factor this
and i get y7
times y+1
which means y=7
ir
y=1
how we doing so far?
you know this stuff? quadratics you canall do some little factor now you have to match, e to the x is 7 
1:31  or e to the x is 1 if e to the x is 7 x is the natural log of 7 and of e to the x i 1 now we get x is the natural log of 1 there is not natural log of 1 in real so this is no solution that make sense? e to the x always has to be something greater than 0 
2:02  can be 0 and cant be a negative
how we doing on this so far?
make sure you understand that..now of course 
2:30  you can have something like wanted to use similar numbers ' so e to the x is 1/x to the positive x 
3:03  and then if you multiply 2 tot he x you get e to the 2x minus 8 equals 7 e to the x and see how i go that step i took this and multiplied 2 by e to the x so now i just subtract e to the x, 7e to the x from both sides 
3:35  so that looks like a quadratic no so to soslve that y= e to the x you get y squared minus 7y minus 8 equals 0 that factors 
4:03  y8, y+1=0 y=8 y=1 remember its naturally y natural e to the x e to the x is 8 or e to the x = 1 you have x is natural log of 8 or or does not exist ecause e to the x has to be greater then 0 
4:34  not equal to 0, greater then 0
everybody happy so far
see something like that on webassign?
you didnt, you might now of course we dont have to use the function e to the x in it we can do another type of function 
5:30  what if i gave you something liek that well i could get y=sinx 
6:08  i would get y squared3y+2=0 you get y2 and y1 equals 0 gand this is easy y=2 or y=1 
6:30  you can say its not actually y, its sinx
this means sinx
equals to
sinx=1
and sinx cant equal 2
why cant sinx equal 2?
whats the biggest sinx can be? 1, right sinx is always between 1 and 1, because of the graph 
7:01  sinx can equal 1 and we all memorize this by now we know thats pi/2 or 90 degrees if youre doing the final and you can put it in degrees but you cant put it in radains put the right answer in degrees and get yourself most of the credit you should be able to do radains by now might get the right answer in degrees and then you out and cant get the radains 
7:33  could you say its the sin inverse of 1, umm
you could
its not 100 percent correct
you should know the sinx 1 is pi/2
you would get some of the credit but you wouldnt get all of the credit
now how can we make this more annoying?
if it said soolve for x, you would say x 
8:05  usually 0 to 2pi otherwise there is an infinity number of places for sinx equals 1 pi/2 5pi/2 9pi/2 3pi/2 all sorts sinx is always between 1 and 1 think about the sin graph 
8:34  same with cosine, cosine is between 1 and 1
so far so good, alright now
go back to this for a second, lets make it slightly more annoying
what would you do if i gave you that?

9:01  e to the 2x6e to the x5 you would do the same thing as before, do the substitution y=e to the x you get y squared 6y 5=0 and now you try and factor it into a facotr 
9:31  no factor, so what do you do?
you use the quadratic formula, the completing the square. why do you got to do that thoug? thats why we invented the quadratic formula thats painful but this is 6 plus or minus the square root of 56 divided by 2 you dont need to divide 
10:00  so that means that e to the x either equals 6 plus the square root of 56/2 or 6 minus the square root of 56/2 now if your savey the square root of 56 is a little bigger then 7 7 squared is 49 so this will come out negative if you didnt get that, i would understand you dont have calculators 
10:31  unless its really screamingly obvious like i said 110 but its alright if you look at the exam at 6 minus the square root of 56/2 you dont need to streess at the exam and not realize its a negative number but anyways, x is the natural log og 6+ square root of 56/2 so its possible to have something like this and use the quadratic formula 
11:02  little trails with that but you know you got the exam youre not concentrating a b+ instead of minus and you look at the exam and say why am i having trouble with number 4 and youre like oh and then later people say oh that sucks 
11:33  we understand these?
one more practice how bout something like this 
12:27  i gave you all sorts of things 
12:30  ln 2 5
will that make you happy?
sure alright how would we solve that? 
13:07  so what do we do on this? well do you remember the rules of logs?
the log of x5 plus log of x2 thats the same as log of x5 times x2 and of course, ln whatever you want to call it 
13:30  is log base e so thats the same as saying x5 times x2 equals e to the 0 and e to the 0 is 1 those are the rules of logs, so you get the log of something plus the log of something thats the same as the single log multiplied together remember natural log is log base e 
14:00  so that means e to the 0 equals whatever this is and e to the 0 is 1 so now we multiply this out and we get x squared minus 7x plus 10 equals 1 or x squared minus 7x plus 9 equals 0 
14:43  so now we factor that but it doesnt factor so you can sing the song when youre doing it 
15:10  so thats
are either of those negative
7+ or minus the square root of 13 /2 is negative?

15:40  no niether of those are negative the square root of 13 is not bigger then 7 7+the square root of 13/2 is positive 7 the square root of 13/2 is positive. they both are positive now thats thats it, your only problem is 
16:02  this happened in webassign 7+the square root of 13/2 minus 5 is positive minus 2 is positive but 7 the square root of 13/2 minus 5 is negative but somehow is expecting that answer anyway put both answer if you were to see something like this but you might not 
16:30  i would write that as seperate answers
i would write 7+the square root of 13/2
and 7=the square root of 13/2
thats just me
so this is the equation type of thing you should solve
have you practice a couple?
i have exacrtly one more so lets make up a couple of these just to make sure you know this 
17:06  try to aviod the quadratic formula, you can do it. your call 
18:27  heres two to get you started 
18:33  so what do we do with this? multiply 2 to the x and we get e to the 2x6=5eto the x or e to the 2x 5e to the x 6 equals 0 so far so good you can factor it out and make any substitutions 
19:01  or not it doesnt really matter but i like to do substitution to keep myself now we got y squared 5y  =0 and that factors quit nicely y6 and y+1 
19:31  so far so good?
are we enjoying ourselves? that means y=6 or y=1 i did this one before e to the x equals 6 e to the x equals negative 1 x equals natural log of 6 x does not exist howd we do on this one? 
20:01  nice and easy
we love this one
now we do one with log
what about this?
wel you can factor out sinx equals 4sin squared x3 equals 0 
20:31  why would i do that?
i know why because now sinx is 0 or this is 0 and that becomes sin squared x equals 3/4 
21:02  qhich means you take the square root
and you get sinx
plus or minus the square root of 3/2
i said plus or minus didnt i
did you remember the plus or minus?
x is 0 equals pi 
21:33  and this means x is ppi/3 2pi/3 4pi/3 or 5pi/3 of course if you put all of them you would get partial but not full credit if you dont get some of the you get some of the all credit 
22:00  and of course you try and do it in radians
enough of this lets do some other stuff
how we doing so far?

22:46  can you solve that so if i subtract two logs thats the same as a single log divided by 
23:09  so far we all go that first step?
we all got partial credit? and that means.. tats a 4 if you cant tell 4 to the 1 equals this 
23:30  4 raised o the 1 which is 4
then you cross multiply
and you get 2x plus 3
equals 4 times
3x plus 1
excited about that?
okay distribute 2x plus 3 equals 12x+4 
24:07  and then you get 1 is 1x x is =1/10 can x be 1/10 it can be negative x can be negative this cant be negative that answer can come out negative as long as your are taking the log of pi/1 
24:34  when you plug in 1/10
they both come out positive thats okay thats your answer
howd we do on that one?
not so much 
25:19  leys see if you can find the inverse lets practice finding the inverse, i suspect this would be an issue so first we replace f of x with y 
25:35  and we switch x and y now we have to isolate y so we divide both sides by 4 and take the natural log of both sides 
26:04  the natural log of x/4 equals 2y1 add 1 and divide by 2 
26:33  that is the inverse function
can we practice another one?
want another with e in it? want a log? make sure we got this? 
27:49  alright find the inverse function of x 
28:02  so we can make this y of 8 and 1+x sqitch variables and x is 8 thats the easy step gets you somewhere but not a lot what do we do with that 8 do the log base 8 of both sides or you can any log of both sides 
28:31  either way which is just easiest now you subtract log and divide by 3 you get log base 8 x minus 1 
29:03  we all see what i did with that one?
alright how bout this? y is 5 log base 4 2x3 switch x and y 
29:38  divide by 5 and then you do 4 to the x5 2y3 and you get 3 
30:09  and you get 4x/5
plus 3 over 2 equals y
howd we do?
now if you have wanted to on this one 
30:36  when youre at the stage x=8 1+3y you couldve taken the log of both sides and do any log you want so for example natural log couldve done this and now you put the 1+3y in front 
31:05  aand you divide and you take it from there subtract one and dive by 3, you couldve done that this is a little smoother but both work put it in the calculator you get the same answer 
31:33  lets practice a couple more of these things 
32:04  okay find the inverse of that so you just switch x and y and then we just have to isolate y so we divide by 5 
32:36  and we cube bot sides and you get x/5 cbed can also be written as x cubed/5 cubed equals 4y1 add 1 and divide by 4 
33:10  how do we feel about invereses?
we love inverse? 
34:07  jeres an entertaining one x+h wel f of x is 5x squared and f of x plus h 
34:30  is 5 x plus h squared minus 3 to the x+h so what you do is fill in both of the x's in x+h x squared plus h have to write x+h squared times x+h now we should simplify this before we do the subtraction 
35:00  this is 5 times x squared plus 2xh plus h squared 3x3h then distribute you get 5x squared plus 10xh plus 5h squared minus 3x minus 3h now if you want to find f of x+h 
35:33  minus f of x this minus this 5x squared plus 10 xh plus 5x squared minus 3x minus 3h minus ex squared minus 3x you have to distribute that minus sign 
36:02  so thats 5x squared plus 10xh plus 5h squaed 3 to the x minus 3h minus 5x squared plus 3x and the 5x squared and the 3x's cancel and you get 10xh plus 5h squared minus 3h 